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1988 United States presidential election in Nevada

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1988 United States presidential election in Nevada

← 1984 November 8, 1988 1992 →
 
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 4 0
Popular vote 206,040 132,738
Percentage 58.86% 37.92%

County Results

Bush

  50–60%
  60–70%
  70–80%

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

The 1988 United States presidential election in Nevada took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

Nevada was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen. Bush carried Nevada with 58.86% of the vote, while Dukakis received 37.92%, a victory margin of 20.94%.

Nevada weighed in for this election as about 13% more Republican than the national average. This was also the last election in which Clark County, the most populated county in Nevada, was won by a Republican presidential candidate.[1]

1988 United States presidential election in Nevada Intro articles: 304